Sep 08

Use static method Integer.parseInt() and catch the exception that is thrown when the number cannot be parsed.

String s = "123";
boolean isValidInteger = false;
try
{
   int i = Integer.parseInt(s);

   // s is a valid integer

   isValidInteger = true;
}
catch (NumberFormatException ex)
{
   // s is not an integer
}

written by objects \\ tags: , ,


Leave a Reply