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	<title>web development helpdesk &#187; sort</title>
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		<title>How to sort Java List using custom ordering</title>
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		<pubDate>Thu, 04 Mar 2010 01:37:26 +0000</pubDate>
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		<guid isPermaLink="false">http://helpdesk.objects.com.au/?p=1419</guid>
		<description><![CDATA[Java provides a convenient Collections.sort() method to sort a List of Object’s. The Objects in the list are required to implement the Comparable interface and the compareTo() method is used to compare Objects. When an alternate sort order is needed you can do that using a Comparator which is passed to the sort() call. The [...]]]></description>
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		<title>How to sort Java array using custom ordering</title>
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		<pubDate>Thu, 04 Mar 2010 01:30:08 +0000</pubDate>
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		<guid isPermaLink="false">http://helpdesk.objects.com.au/?p=1415</guid>
		<description><![CDATA[Java provides a convenient Arrays.sort() method to sort an array of Object&#8217;s. The Objects in the array are required to implement the Comparable interface and the compareTo() method is used to compare Objects. When an alternate sort order is needed you can do that using a Comparator which is passed to the sort() call. The [...]]]></description>
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		<title>How do I find the smallest value in an array?</title>
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		<pubDate>Thu, 25 Sep 2008 02:33:58 +0000</pubDate>
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		<guid isPermaLink="false">http://helpdesk.objects.com.au/?p=262</guid>
		<description><![CDATA[One solution would be to loop through the array maintaining the smallest value found in a variable. Another solution would be to first sort the array, then the smallest value would be the first element. int[] values = { 2, 67, 15, 3, 567 }; // first approach int smallest = values[0]; for (int i=1; [...]]]></description>
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		<title>How do I find the largest value in an array?</title>
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		<pubDate>Thu, 25 Sep 2008 02:20:52 +0000</pubDate>
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		<guid isPermaLink="false">http://helpdesk.objects.com.au/?p=258</guid>
		<description><![CDATA[One solution would be to loop through the array maintaining the largest value found in a variable. Another solution would be to first sort the array, then the largest value would be the last element. int[] values = { 2, 67, 15, 3, 567 }; // first approach int largest = values[0]; for (int i=1; [...]]]></description>
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		<title>How do I use Collections.sort() with generics?</title>
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		<pubDate>Thu, 25 Sep 2008 02:19:10 +0000</pubDate>
		<dc:creator>objects</dc:creator>
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		<guid isPermaLink="false">http://helpdesk.objects.com.au/?p=254</guid>
		<description><![CDATA[import java.util.ArrayList; import java.util.Collections; import java.util.List; public class MyBean implements Comparable&#60;MyBean&#62; { private int value; public MyBean() { } public MyBean(int value) { setValue(value); } public int getValue() { return value; } public void setValue(int value) { this.value = value; } public int compareTo(MyBean other) { return value - other.value; } public String toString() { [...]]]></description>
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		<title>How do I create a sorted Set?</title>
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		<pubDate>Tue, 23 Sep 2008 01:20:01 +0000</pubDate>
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		<description><![CDATA[The TreeSet class maintains its elements in order. Set&#60;String&#62; set = new TreeSet&#60;String&#62;(); set.add(&#34;one&#34;); set.add(&#34;two&#34;); set.add(&#34;three&#34;); for (String s : set) { System.out.println(s); } // Output will be (as String&#039;s are sorted alpabetically): // one // three // two Related posts: How to create a tar archive using Java Java doesn&#8217;t provide standard support for [...]]]></description>
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